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=52A^2
We move all terms to the left:
-(52A^2)=0
a = -52; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-52)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$A=\frac{-b}{2a}=\frac{0}{-104}=0$
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